Which aqueous solution has the lowest vapor pressure glucose?

The solution with the lowest vapor pressure is glucose with χ = 0.25. The equation for vapor pressure of a solution is P°=χsolvent∙P where P° is the vapor pressure of the solution, χ is the mole fraction of the solvent, and P is the vapor pressure of the pure solvent.

Why is the vapour pressure of aqueous solution of glucose lower than that of water?

(a) A part of the water surface is occupied by non – volatile glucose molecules. This decreases the effective surface area for the vaporization of water molecules. Consequently, the vapour pressure of solution of glucose in water is lower than that of water.

How do you find the molar mass of an unknown solute?

Step 1: List the known quantities and plan the problem. Use the freeing point depression (ΔTf) to calculate the molality of the solution. Then use the molality equation to calculate the moles of solute. Then divide the grams of solute by the moles to determine the molar mass.

What is KF water?

For water, the value of Kf is −1.86oC/m. So, the freezing temperature of a 1-molal aqueous solution of any nonvolatile molecular solute is −1.86oC. Every solvent has a unique molal freezing-point depression constant.

Which aqueous solution has lowest freezing point?

Dividing by 6.02×1023 we can see that the comparative figures are NaCl, 2 , Na2SO4 ,0.9 , glucose , 1.5 , and BaSO4. 1.5 Thus , the NaCl solution has the greatest number of particles per unit volume (considering the ionization of NaCl , Na2SO4andBaSO4) and its will have the lowest freezing point.

Is glucose a non-volatile solute?

Urea, $NaCl$, glucose and sucrose are examples of non-volatile solute. The substances that cannot be vaporized easily are known as non-volatile solutes.

Why boiling point of aqueous solution of glucose is higher than that of water?

This is because KCl dissociates in water to give two ions (KCI→k4+Cl-), whereas glucose does not dissociate. Therefore, number of solute particles is greater in 0.1 m KCl as compared to 0.1 m glucose. Hence, elevation in boiling points in 0.1 m KCl will be higher and therefore, its boiling point will be higher.

What is Raoult’s Law for volatile solute?

Raoult’s Law for Volatile Solutes Raoult’s law states that in a solution, the vapour pressure of a component at a given temperature is equal to the mole fraction of that component in the solution multiplied by the vapour pressure of that component in the pure state.

What is the molar mass of glucose?

180.156 g/molGlucose / Molar mass